Sodium and copper have work functions 2.3 eV | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The work function $\Phi$ is related to the threshold wavelength $\lambda_0$ by the equation: $\Phi = \frac{hc}{\lambda_0}$.This implies that $\lam

Vedclass · Accepted Answer

$2: 1$

Vedclass · Answer

(B) The work function $\Phi$ is related to the threshold wavelength $\lambda_0$ by the equation: $\Phi = \frac{hc}{\lambda_0}$.This implies that $\lambda_0 = \frac{hc}{\Phi}$.Let $\Phi_{Na} = 2.3 \ eV$ and $\Phi_{Cu} = 4.5 \ eV$.The ratio of the threshold wavelengths is given by: $\frac{\lambda_{Na}}{\lambda_{Cu}} = \frac{hc / \Phi_{Na}}{hc / \Phi_{Cu}} = \frac{\Phi_{Cu}}{\Phi_{Na}}$.Substituting the given values: $\frac{\lambda_{Na}}{\lambda_{Cu}} = \frac{4.5}{2.3} \approx 1.956$.Rounding this value to the nearest option,we get $2: 1$.

Sodium and copper have work functions $2.3 \ eV$ and $4.5 \ eV$ respectively. The ratio of the threshold wavelength of sodium to that of copper is nearest to:

Similar Questions

The reaction($s$) leading to the formation of $1,3,5$-trimethylbenzene is (are)

The circle $4x^2 + 4y^2 - 12x - 12y + 9 = 0$

The incentre of the triangle with vertices $(1, \sqrt{3})$,$(0, 0)$ and $(2, 0)$ is

Which of the following is paramagnetic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module