The reaction of benzene with CO and HCl in th | vedclass

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(C) The reaction of benzene with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ is the Gattermann-Koch reaction,which produces benzaldehyde $(C_

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Benzoyl chloride reacting with $H_2-Pd$ and $BaSO_4$

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(C) The reaction of benzene with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ is the Gattermann-Koch reaction,which produces benzaldehyde $(C_6H_5CHO)$. Thus,$X$ is benzaldehyde.Let us analyze the given options:$A$: Benzonitrile $(C_6H_5CN)$ on reduction with $LiAlH_4$ gives benzylamine $(C_6H_5CH_2NH_2)$.$B$: Toluene $(C_6H_5CH_3)$ on oxidation with $KMnO_4 | OH^-$ gives benzoic acid $(C_6H_5COOH)$.$C$: Benzoyl chloride $(C_6H_5COCl)$ on reduction with $H_2-Pd$ and $BaSO_4$ (Rosenmund reduction) gives benzaldehyde $(C_6H_5CHO)$.$D$: Benzyl alcohol $(C_6H_5CH_2OH)$ on oxidation with $CrO_3-H_2SO_4$ (Jones reagent) gives benzoic acid $(C_6H_5COOH)$.Therefore,benzaldehyde is obtained in reaction $C$.

The reaction of benzene with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ gives a compound $X$. $X$ can also be obtained from which of the following reactions?

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