The reaction 2 C_6H_6 + CH_2Cl_2 xrightarrow{ | vedclass

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Question

(B) The reaction is a Friedel-Crafts alkylation. Benzene reacts with dichloromethane $(CH_2Cl_2)$ in the presence of a Lewis acid catalyst like $AlCl_

Vedclass · Accepted Answer

$Ph-CH_2-Ph$

Vedclass · Answer

(B) The reaction is a Friedel-Crafts alkylation. Benzene reacts with dichloromethane $(CH_2Cl_2)$ in the presence of a Lewis acid catalyst like $AlCl_3$. The electrophile $CH_2Cl^{+}$ attacks the benzene ring to form benzyl chloride $(Ph-CH_2Cl)$. This intermediate then reacts with another molecule of benzene to form diphenylmethane $(Ph-CH_2-Ph)$. The overall reaction is: $2 C_6H_6 + CH_2Cl_2 \xrightarrow{AlCl_3} Ph-CH_2-Ph + 2 HCl$.

The reaction $2 C_6H_6 + CH_2Cl_2 \xrightarrow{AlCl_3, \Delta} ?$ gives the major product:

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