The ratio of the present ages of $A$ and $B$ is $7:9$. $6$ years ago,the ratio of $\frac{1}{3}$ of $A$'s age at that time and $\frac{1}{3}$ of $B$'s age at that time was $1:2$. What will be the ratio of $A$'s to $B$'s age $6$ years from now?

The sum of the ages of a father and son is $45$ years. $5$ years ago,the product of their ages was four times the father's age at that time. The present age of the father is (in years):

The ratio of the ages of $Ram$ and $Rahim, 10$ years ago was $1:3$. The ratio of their ages $5$ years hence will be $2:3$. Then the ratio of their present ages is:

One $year$ ago,a father was four times as old as his son. In $6$ $years$ time,his age will exceed twice his son's age by $9$ $years$. The ratio of their present ages is:

In a family,a couple has a son and a daughter. The age of the father is three times that of his daughter and the age of the son is half of his mother. The wife is $9$ years younger than her husband and the brother is $7$ years older than his sister. What is the age of the mother? (in years)

The present age of Romila is $\frac{1}{4}$ that of her father. After $6\, \text{years}$, her father's age will be twice the age of Kapil. If Kapil celebrated his fifth birthday $8\, \text{years}$ ago, what is Romila's present age? (in $\text{years}$)