The ratio of the kinetic energy to the total | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the Bohr model of the hydrogen atom,the kinetic energy $(K.E.)$ of an electron in an orbit is given by $K.E. = \frac{kZe^2}{2r}$.The total ener

Vedclass · Accepted Answer

-$1$

Vedclass · Answer

(A) In the Bohr model of the hydrogen atom,the kinetic energy $(K.E.)$ of an electron in an orbit is given by $K.E. = \frac{kZe^2}{2r}$.The total energy $(T.E.)$ of the electron in the same orbit is given by $T.E. = -\frac{kZe^2}{2r}$.Comparing these two expressions,we can see that $K.E. = -(T.E.)$.Therefore,the ratio of the kinetic energy to the total energy is $\frac{K.E.}{T.E.} = \frac{K.E.}{-K.E.} = -1$.

The ratio of the kinetic energy to the total energy of an electron in a Bohr orbit is

Similar Questions

The momentum of an electron revolving in the $n^{\text{th}}$ orbit is given by: (Symbols have their usual meanings)

The Rydberg constant $R$ for hydrogen is

An electron revolving in the $n^{\text{th}}$ Bohr orbit has a magnetic moment $\mu_n$. If $\mu_n \propto n^x$,the value of $x$ is:

An excited hydrogen atom emits a photon of wavelength $\lambda$ in returning to the ground state. The quantum number $n$ of the excited state is ($R=$ Rydberg's constant).

When an electron jumps from the $n = 4$ level to the $n = 1$ level,the angular momentum of the electron changes by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module