The ratio of the maximum and minimum magnitud | vedclass

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(B) The maximum magnitude of the resultant of two vectors $\vec{a}$ and $\vec{b}$ is given by $R_{	ext{max}} = |\vec{a}| + |\vec{b}| = a + b$.The min

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$2|\vec{b}|$

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(B) The maximum magnitude of the resultant of two vectors $\vec{a}$ and $\vec{b}$ is given by $R_{	ext{max}} = |\vec{a}| + |\vec{b}| = a + b$.The minimum magnitude of the resultant is given by $R_{	ext{min}} = |\vec{a}| - |\vec{b}| = a - b$ (assuming $a > b$).Given the ratio $\frac{R_{	ext{max}}}{R_{	ext{min}}} = \frac{3}{1}$.Substituting the expressions,we get $\frac{a + b}{a - b} = \frac{3}{1}$.Cross-multiplying,we get $a + b = 3(a - b)$.$a + b = 3a - 3b$.Rearranging the terms,$4b = 2a$.Therefore,$a = 2b$,which means $|\vec{a}| = 2|\vec{b}|$.

The ratio of the maximum and minimum magnitudes of the resultant of two vectors $\vec{a}$ and $\vec{b}$ is $3 : 1$. Then $|\vec{a}|$ is equal to:

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