In a galvanometer,the deflection becomes one half when the galvanometer is shunted by a $20\,\Omega$ resistor. The galvanometer resistance is ............... $\Omega$.

$A$ galvanometer of resistance $50 \ \Omega$ is connected to a battery of $8 \ V$ along with a resistance of $3950 \ \Omega$ in series. $A$ full-scale deflection of $30$ divisions is obtained in the galvanometer. In order to reduce this deflection to $15$ divisions,the resistance in series should be . . . . . . $\Omega$.

$A$ galvanometer has a resistance of $50 \ \Omega$ and it allows a maximum current of $5 \ mA$. It can be converted into a voltmeter to measure up to $100 \ V$ by connecting in series a resistor of resistance: (in $Omega$)

An ammeter of $5\,\Omega$ resistance can read $5\,mA$. If it is to be used to read $100\,V$,how much resistance is to be connected in series? (in $\Omega$)

How can we convert a galvanometer into an ammeter?

In order to pass $10\,\%$ of the main current through a moving coil galvanometer of $99\,\Omega$,the resistance of the required shunt is ............ $\Omega$.