The ratio of de Broglie wavelengths of two particles,having mass ratio $1 : 3$ and kinetic energy ratio $2 : 1$ is

Out of an electron and a proton,which one will have a higher velocity to produce matter waves of the same wavelength? Explain.

The wavelength of a microscopic particle of mass $9.1 \times 10^{-31} \ kg$ is $182 \ nm$. Its kinetic energy in $J$ is: $(h = 6.625 \times 10^{-34} \ J \ s)$

The wavelength (in $m$) of a particle of mass $11.043 \times 10^{-26} \ kg$ moving with a velocity of $6.0 \times 10^7 \ ms^{-1}$ is $.......$

Two particles of masses $m$ and $2m$ have equal kinetic energies. The de-Broglie wavelengths are in the ratio of

If $v_0$ is the threshold frequency of a metal $X$,the correct relation between de Broglie wavelength $(\lambda)$ associated with the photoelectron and the frequency $(v)$ of the incident radiation is: