The ratio in which the point $(5, -2)$ divides the line segment joining the points $(8, 4)$ and $(9, 6)$ is:

If $A(2,-1,1)$,$B(2,5,1)$,and $C(0,-2,3)$ are the vertices of a triangle,and $D$ is the point of intersection of the side $BC$ and the internal angular bisector of angle $A$,then $AD=$

Points $A(3, 2, 4)$,$B\left(\frac{33}{5}, \frac{28}{5}, \frac{38}{5}\right)$ and $C(9, 8, 10)$ are given. The ratio in which $B$ divides $\overline{AC}$ is

If $A(4,3,2), B(5,4,6), C(-1,-1,5)$ are the vertices of a triangle,then the coordinates of the point in which the bisector of the angle $A$ meets the side $BC$ is

The point dividing the line segment joining $(3, -2, 1)$ and $(-2, 3, 11)$ in the ratio $2:3$ is

Using the section formula,show that the points $A(2, -3, 4)$,$B(-1, 2, 1)$,and $C(0, \frac{1}{3}, 2)$ are collinear.