The rate constant of a first-order reaction i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a first-order reaction,the rate constant $k$ is given by the formula: $k = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$.Given: $k = 1.20 	imes 1

Vedclass · Accepted Answer

$426$

Vedclass · Answer

(A) For a first-order reaction,the rate constant $k$ is given by the formula: $k = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$.Given: $k = 1.20 	imes 10^{-3} \, s^{-1}$,$[A]_0 = 5 \, g$,and $[A]_t = 3 \, g$.Substituting the values: $1.20 	imes 10^{-3} = \frac{2.303}{t} \log \frac{5}{3}$.$t = \frac{2.303}{1.20 	imes 10^{-3}} 	imes \log(1.666)$.$t = \frac{2.303}{1.20 	imes 10^{-3}} 	imes 0.2218$.$t \approx 425.6 \, s \approx 426 \, s$.

The rate constant of a first-order reaction is $1.20 \times 10^{-3} \, s^{-1}$. How much time will it take for $5 \, g$ of the reactant to reduce to $3 \, g$ (in $, s$)?

Similar Questions

For a first order reaction $A \rightarrow \text{Products}$,initial concentration of $A$ is $0.1 \, M$,which becomes $0.001 \, M$ after $5 \, \min$. Rate constant for the reaction in $\min^{-1}$ is .... .

Half-life and rate constant for a first-order reaction are related by the equation:

$A$ reaction has a rate constant $k = 2.4 \times 10^{-4} \ s^{-1}$. Find the ratio of $t_{99.9}$ to $t_{50}$.

For a first-order reaction,if $75\%$ of the reaction is completed in $15 \ min$,then the time required for $90\%$ completion of the reaction will be ........... $min$.

If the rate constant for a first order reaction is $k$,the time $(t)$ required for the completion of $99\%$ of the reaction is given by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module