The radius of the orbit of an electron in a H | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The radius of an orbit in a hydrogen atom is given by $R_n = n^2 a_0$,where $a_0 = 0.53 \mathring{A}$.For the initial state: $2.12 = n_1^2 	imes

Vedclass · Accepted Answer

Absorbed a photon of energy $1.89 \ eV$

Vedclass · Answer

(B) The radius of an orbit in a hydrogen atom is given by $R_n = n^2 a_0$,where $a_0 = 0.53 \mathring{A}$.For the initial state: $2.12 = n_1^2 	imes 0.53 \implies n_1^2 = 4 \implies n_1 = 2$.For the final state: $4.77 = n_2^2 	imes 0.53 \implies n_2^2 = 9 \implies n_2 = 3$.Since the radius increases,the electron has transitioned from a lower energy level to a higher energy level,meaning the atom has absorbed a photon.The energy of the absorbed photon is $\Delta E = E_3 - E_2 = -13.6 \left( \frac{1}{3^2} - \frac{1}{2^2} ight) \ eV$.$\Delta E = -13.6 \left( \frac{1}{9} - \frac{1}{4} ight) = -13.6 \left( \frac{4-9}{36} ight) = -13.6 \left( -\frac{5}{36} ight) \ eV$.$\Delta E = \frac{68}{36} \ eV \approx 1.89 \ eV$.

The radius of the orbit of an electron in a $H$-atom changes from $2.12 \mathring{A}$ to $4.77 \mathring{A}$. The $H$-atom has:

Similar Questions

The electron in a hydrogen atom is moving in an orbit of radius $0.53 \text{ Å}$. It takes $1.571 \times 10^{-16} \text{ s}$ to complete one revolution. The velocity of the electron will be $[\pi = 3.142]$.

$P$ is the probability of finding the $1s$ electron of a hydrogen atom in a spherical shell of infinitesimal thickness, $dr$, at a distance $r$ from the nucleus. The volume of this shell is $4\pi r^2 dr$. The qualitative sketch of the dependence of $P$ on $r$ is:

The ground state energy of a hydrogen atom is $-13.6 \ eV$. In this state,the potential energy is . . . . . . $eV$.

The radius of a hydrogen atom in the ground state is $0.53 \ Å$. After collision with an electron,it is found to have a radius of $2.12 \ Å$. The principal quantum number $n$ of the final state of the atom is:

The radius of the innermost orbit of a hydrogen atom is $5.3 \times 10^{-11} \ m$. The radius of the third allowed orbit of the hydrogen atom is $... \ \mathring{A}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module