The radius of the nucleus of an atom whose mass number is $125$ is:
- A$1 \times 10^{-15} \ m$
- B$6 \times 10^{-15} \ m$
- C$10 \times 10^{-15} \ m$
- D$16 \times 10^{-15} \ m$
Explore More
Similar Questions
$F_{pp}$,$F_{nn}$,and $F_{np}$ are the nuclear forces between proton-proton,neutron-neutron,and neutron-proton respectively. Then the relation between them is:
$A$ heavy nucleus at rest breaks into two fragments which fly off with velocities in the ratio $3: 1$. The ratio of radii of the fragments is
The radius of ${ }_{52} Te^{125}$ nucleus is $6 \text{ fermi}$. The radius of ${ }_{13} Al^{27}$ nucleus in meters is
DifficultAP EAMCET 2013
View SolutionThe radius of a Germanium $(Ge)$ nucleus is twice the radius of a $^9_4Be$ nucleus. The number of nucleons in $Ge$ is ......
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo