The radius of { }_{52} Te^{125} nucleus is 6 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relation between the radius $(R)$ and the mass number $(A)$ of a nucleus is given by $R = R_0 A^{1/3}$.Therefore,the ratio of the radii of two

Vedclass · Accepted Answer

$3.6 	imes 10^{-15} 	ext{ m}$

Vedclass · Answer

(B) The relation between the radius $(R)$ and the mass number $(A)$ of a nucleus is given by $R = R_0 A^{1/3}$.Therefore,the ratio of the radii of two nuclei is given by $\frac{R_1}{R_2} = \left(\frac{A_1}{A_2}ight)^{1/3}$.Given: $R_1 = 6 	ext{ fermi}$,$A_1 = 125$,and $A_2 = 27$.Substituting the values:$\frac{6}{R_2} = \left(\frac{125}{27}ight)^{1/3} = \frac{5}{3}$.Solving for $R_2$:$R_2 = \frac{6 	imes 3}{5} = \frac{18}{5} = 3.6 	ext{ fermi}$.Since $1 	ext{ fermi} = 10^{-15} 	ext{ m}$,we have $R_2 = 3.6 	imes 10^{-15} 	ext{ m}$.

The radius of ${ }_{52} Te^{125}$ nucleus is $6 \text{ fermi}$. The radius of ${ }_{13} Al^{27}$ nucleus in meters is

Similar Questions

The volume of a nucleus is directly proportional to

Mass numbers of two nuclei are in the ratio of $4: 3$. Their nuclear densities will be in the ratio of

Consider the following two statements,$A$ and $B$ and identify the correct answer given below:
$A$. Nuclear density is same for all nuclei.
$B$. Radius of the nucleus $R$ and its mass number $A$ are related as $\sqrt{A} \propto R^{1 / 6}$.

$1\,U = ...... \text{kg}$. How is the mass of an atom or nucleus determined?

The nuclear radius of a hydrogen atom is approximately . . . . . . . (in $fm$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module