The radius of germanium (Ge) nuclide is measu | vedclass

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(A) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant and $A$ is the mass number (number of nucleons).Given

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$72$

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(A) The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,where $R_0$ is a constant and $A$ is the mass number (number of nucleons).Given that the radius of $Ge$ is twice the radius of ${}_4^9Be$,we have:$R_{Ge} = 2 R_{Be}$Using the formula $R \propto A^{1/3}$:$\frac{R_{Ge}}{R_{Be}} = \left( \frac{A_{Ge}}{A_{Be}} ight)^{1/3}$Substituting the given values:$2 = \left( \frac{A_{Ge}}{9} ight)^{1/3}$Cubing both sides:$2^3 = \frac{A_{Ge}}{9}$$8 = \frac{A_{Ge}}{9}$$A_{Ge} = 8 	imes 9 = 72$Therefore,the number of nucleons in $Ge$ is $72$.

The radius of germanium $(Ge)$ nuclide is measured to be twice the radius of ${}_4^9Be$. The number of nucleons in $Ge$ are

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