The radius of a sphere is $7 \text{ cm}$. If an error of $0.08 \text{ cm}^2$ is made in measuring its surface area,then the approximate error (in $\text{cm}^3$) found in its volume is:

  • A
    $0.28$
  • B
    $0.32$
  • C
    $0.96$
  • D
    $0.098$

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