The radius of a right circular cylinder is in | vedclass

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(D) Let the initial radius be $r = 10$ and height be $H$.Initial volume $V_1 = \pi r^2 H = \pi (10)^2 H = 100 \pi H$.Since the radius is increased by

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$125$

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(D) Let the initial radius be $r = 10$ and height be $H$.Initial volume $V_1 = \pi r^2 H = \pi (10)^2 H = 100 \pi H$.Since the radius is increased by $50 \%$,the new radius $r' = 10 + (50 \% 	ext{ of } 10) = 10 + 5 = 15$.The height $H$ remains constant.New volume $V_2 = \pi (r')^2 H = \pi (15)^2 H = 225 \pi H$.The increase in volume $= V_2 - V_1 = 225 \pi H - 100 \pi H = 125 \pi H$.Percentage increase in volume $= \left( \frac{V_2 - V_1}{V_1} ight) 	imes 100 = \left( \frac{125 \pi H}{100 \pi H} ight) 	imes 100 = 125 \%.$

The radius of a right circular cylinder is increased by $50 \% .$ Find the percentage increase in volume (in $\%$)?

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