A rectangular park is 65, m long and 50, m wi | vedclass

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(C) The length of the rectangular park is $L = 65\, m$ and the width is $W = 50\, m$.The width of the paths is $w = 2\, m$.The area of the path parall

Vedclass · Accepted Answer

$3898.50$

Vedclass · Answer

(C) The length of the rectangular park is $L = 65\, m$ and the width is $W = 50\, m$.The width of the paths is $w = 2\, m$.The area of the path parallel to the length is $L 	imes w = 65 	imes 2 = 130\, m^2$.The area of the path parallel to the width is $W 	imes w = 50 	imes 2 = 100\, m^2$.Since the two paths intersect at the center,the intersection area is a square of side $w = 2\, m$,which is $w^2 = 2 	imes 2 = 4\, m^2$.The total area of the paths is $(130 + 100 - 4) = 226\, m^2$.The cost of construction is $226 	imes 17.25 = ₹ 3898.50$.

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