The radius of a circular ground is $90\, m$. Inside it, a road of width $10\, m$ runs around its boundary. Find the area of the road. $(\pi=3.14)$ (in $m^2$)
$5216$
$4535$
$5139$
$5338$
In covering a distance $s$ metres, a circular wheel of radius $r$ metres makes $\frac{s}{2 \pi r}$ revolutions. Is this statement true? Why?
In $\odot( O , 7),$ the length of $\widehat{ ABC }$ is $14 .$ Then, $\ldots \ldots .$ holds good.
The central angles of two sectors of circles of radii $7 \,cm$ and $21\, cm$ are respectively $120^{\circ}$ and $40^{\circ}$. Find the areas of the two sectors as well as the lengths of the corresponding arcs. What do you observe?
In a circle with radius $20 \,cm$, the measures of the angle subtended at the centre for two distinct sectors are $15$ and $90 .$ Then, the ratio of the areas of those sectors is $\ldots \ldots \ldots .$
The area of a sector formed by a $12\,cm$ long arc in a circle with radius $12\,cm$ is $\ldots \ldots \ldots . . cm ^{2}$.