The radius and height of a cylindrical coin a | vedclass

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Question

(B) For a single cylindrical coin:Radius $(r) = 1.4 \, cm = \frac{14}{10} \, cm$Height $(h) = 0.1 \, cm = \frac{1}{10} \, cm$Volume of one coin $= \pi

Vedclass · Accepted Answer

$36.96$

Vedclass · Answer

(B) For a single cylindrical coin:Radius $(r) = 1.4 \, cm = \frac{14}{10} \, cm$Height $(h) = 0.1 \, cm = \frac{1}{10} \, cm$Volume of one coin $= \pi r^2 h = \frac{22}{7} 	imes (\frac{14}{10})^2 	imes \frac{1}{10} \, cm^3$$= \frac{22}{7} 	imes \frac{196}{100} 	imes \frac{1}{10} = \frac{22 	imes 28}{1000} = \frac{616}{1000} \, cm^3 = 0.616 \, cm^3$Since $60$ such coins are stacked to form a larger cylinder,the total volume is:Total Volume $= 60 	imes 0.616 \, cm^3 = 36.96 \, cm^3$.

The radius and height of a cylindrical coin are $1.4 \, cm$ and $0.1 \, cm$ respectively. $60$ such coins are stacked up to make a larger cylindrical pillar. Find the volume of this larger cylinder (in $cm^3$).

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