The radii of two cylinders are in the ratio 3 | vedclass

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(C) Let the radii of the two cylinders be $r_1$ and $r_2$,and their heights be $h_1$ and $h_2$.Given that $r_1 : r_2 = 3 : 7$ and $h_1 : h_2 = 28 : 15

Vedclass · Accepted Answer

$4: 5$

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(C) Let the radii of the two cylinders be $r_1$ and $r_2$,and their heights be $h_1$ and $h_2$.Given that $r_1 : r_2 = 3 : 7$ and $h_1 : h_2 = 28 : 15$.The curved surface area $(CSA)$ of a cylinder is given by the formula $CSA = 2pi rh$.Therefore,the ratio of their curved surface areas is:$\frac{CSA_1}{CSA_2} = \frac{2pi r_1 h_1}{2pi r_2 h_2} = \frac{r_1}{r_2} 	imes \frac{h_1}{h_2}$Substituting the given ratios:$\frac{CSA_1}{CSA_2} = \frac{3}{7} 	imes \frac{28}{15}$$\frac{CSA_1}{CSA_2} = \frac{3}{15} 	imes \frac{28}{7} = \frac{1}{5} 	imes 4 = \frac{4}{5}$Thus,the ratio of their curved surface areas is $4 : 5$.

The radii of two cylinders are in the ratio $3: 7$ and their heights are in the ratio $28: 15$. Calculate the ratio of their curved surface areas.

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