The radii of curvature for a thin convex lens | vedclass

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(C) Using the Lens Maker's Formula: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a convex lens,$R_1 = +10 \ cm$ and $R_2

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$1.5$

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(C) Using the Lens Maker's Formula: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a convex lens,$R_1 = +10 \ cm$ and $R_2 = -15 \ cm$.The focal length $f = +12 \ cm$.Substituting the values: $\frac{1}{12} = (\mu - 1) \left( \frac{1}{10} - \frac{1}{-15} \right)$.$\frac{1}{12} = (\mu - 1) \left( \frac{1}{10} + \frac{1}{15} \right)$.$\frac{1}{12} = (\mu - 1) \left( \frac{3 + 2}{30} \right) = (\mu - 1) \left( \frac{5}{30} \right)$.$\frac{1}{12} = (\mu - 1) \left( \frac{1}{6} \right)$.$\mu - 1 = \frac{6}{12} = 0.5$.$\mu = 1.5$.

The radii of curvature for a thin convex lens are $10 \ cm$ and $15 \ cm$ respectively. The focal length of the lens is $12 \ cm$. The refractive index of the lens material is:

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