The quadratic equation having roots -1 and 2 | vedclass

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Question

(D) quadratic equation with roots $\alpha$ and $\beta$ is given by the formula: $(x - \alpha)(x - \beta) = 0$.
Given the roots are $\alpha = -1$ and

Vedclass · Accepted Answer

$x^{2}-x-2=0$

Vedclass · Answer

(D) quadratic equation with roots $\alpha$ and $\beta$ is given by the formula: $(x - \alpha)(x - \beta) = 0$.
Given the roots are $\alpha = -1$ and $\beta = 2$.
Substituting these values into the formula,we get: $(x - (-1))(x - 2) = 0$.
This simplifies to: $(x + 1)(x - 2) = 0$.
Expanding the expression: $x(x) + x(-2) + 1(x) + 1(-2) = 0$.
$x^{2} - 2x + x - 2 = 0$.
$x^{2} - x - 2 = 0$.
Therefore,the correct quadratic equation is $x^{2} - x - 2 = 0$.

The quadratic equation having roots $-1$ and $2$ is .... .

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