The quadratic equation $2x^{2} - (a^{3} + 8a - 1)x + a^{2} - 4a = 0$ has roots of opposite signs. Then,

  • A
    $a \leq 0$
  • B
    $0 < a < 4$
  • C
    $4 \leq a < 8$
  • D
    $a \geq 8$

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