The purple colour of KMnO_4 is due to the tra | vedclass

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Question

The permanganate ion has an intense purple colour. $Mn$  $(+ VII)$ has a $d^0$ configuration. So the colour arises from charge transfer and not f

Vedclass · Accepted Answer

$C.T. \,(L 	o M)$

Vedclass · Answer

The permanganate ion has an intense purple colour. $Mn$  $(+ VII)$ has a $d^0$ configuration. So the colour arises from charge transfer and not from $d - d$ spectra.

In $\mathrm{MnO}_{4}^{-}$ an electron is momentarily changing $\mathrm{O}^{--}$ to $\mathrm{O}^{-}$ and reducing the oxidation state of the metal from $Mn\,(VII)$ to $Mn\, (VI)$. Charge transfer requires that the energy levels on the two different atoms are fairly close.

$\,\begin{array}{*{20}{c}}
  {O\, = \,(8)\, = 2,} \ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,K} 
\end{array}\,\begin{array}{*{20}{c}}
  {6\,;} \ 
  L 
\end{array}$           $\,\begin{array}{*{20}{c}}
  {Mn\,\,(25)\, = 2,} \ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,K} 
\end{array}\,\begin{array}{*{20}{c}}
  {8,} \ 
  L 
\end{array}\begin{array}{*{20}{c}}
  {15} \ 
  M 
\end{array}$

Hence the charge transfer occurs from

$L	o M$

The purple colour of $KMnO_4$ is due to the transition

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