The products formed when an aqueous solution | vedclass

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Question

(C) In an aqueous solution,$NaBr$ dissociates as: $NaBr(aq) 	o Na^{+}(aq) + Br^{-}(aq)$.Water also dissociates slightly: $H_2O(l) ightleftharpoons

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$H_2, Br_2$ and $NaOH$

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(C) In an aqueous solution,$NaBr$ dissociates as: $NaBr(aq) 	o Na^{+}(aq) + Br^{-}(aq)$.Water also dissociates slightly: $H_2O(l) ightleftharpoons H^{+}(aq) + OH^{-}(aq)$.At the cathode,the reduction of water is preferred over $Na^{+}$ ions: $2H_2O(l) + 2e^{-} 	o H_2(g) + 2OH^{-}(aq)$.At the anode,the oxidation of $Br^{-}$ ions is preferred over water: $2Br^{-}(aq) 	o Br_2(l) + 2e^{-}$.The $Na^{+}$ ions remain in the solution and combine with $OH^{-}$ ions to form $NaOH$.Thus,the final products are $H_2(g)$,$Br_2(l)$,and $NaOH(aq)$.

The products formed when an aqueous solution of $NaBr$ is electrolysed in a cell having inert electrodes are

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