The product(s) of the reaction NaBH_4 + I_2 l | vedclass

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(C) $NaBH_4$ is a mild reducing agent. When sodium borohydride reacts with iodine,it produces diborane,sodium iodide,and hydrogen gas. This reaction i

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$B_2H_6 + 2NaI + H_2$

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(C) $NaBH_4$ is a mild reducing agent. When sodium borohydride reacts with iodine,it produces diborane,sodium iodide,and hydrogen gas. This reaction involves the oxidation of sodium borohydride with iodine in diglyme to yield diborane. This approach is common in the industrial production of $B_2H_6$. The balanced chemical equation is: $2NaBH_4 + I_2 \xrightarrow{	ext{Diglyme}} B_2H_6 + 2NaI + H_2$

The product$(s)$ of the reaction $NaBH_4 + I_2 \longrightarrow$ 'Products' is/are

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