In which of the following reactions,hydrogen | vedclass

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(A) $I$. $2NaBH_4 + I_2 \rightarrow B_2H_6 + 2NaI + H_2 \uparrow$ (Hydrogen is evolved)$II$. $B_2H_6 + 3O_2 \rightarrow B_2O_3 + 3H_2O$ (No hydrogen i

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$I, IV$ only

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(A) $I$. $2NaBH_4 + I_2 \rightarrow B_2H_6 + 2NaI + H_2 \uparrow$ (Hydrogen is evolved)$II$. $B_2H_6 + 3O_2 \rightarrow B_2O_3 + 3H_2O$ (No hydrogen is evolved)$III$. $8BF_3 + 6NaH \rightarrow B_2H_6 + 6NaBF_4$ (No hydrogen is evolved)$IV$. $B_2H_6 + 6H_2O \rightarrow 2H_3BO_3 + 6H_2 \uparrow$ (Hydrogen is evolved)Thus,in reactions $I$ and $IV$,hydrogen gas is evolved.

In which of the following reactions,hydrogen is evolved?
$I$. Reaction of sodium borohydride with iodine
$II$. Oxidation of diborane
$III$. Reaction of boron trifluoride with sodium hydride
$IV$. Hydrolysis of diborane

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In which of the following reactions,hydrogen is evolved?$I$. Reaction of sodium borohydride with iodine$II$. Oxidation of diborane$III$. Reaction of boron trifluoride with sodium hydride$IV$. Hydrolysis of diborane