The product of two numbers is 120. The sum of | vedclass

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(B) Let the two numbers be $a$ and $b$.Given that the product of the numbers is $ab = 120$.Given that the sum of their squares is $a^2 + b^2 = 289$.We

Vedclass · Accepted Answer

$23$

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(B) Let the two numbers be $a$ and $b$.Given that the product of the numbers is $ab = 120$.Given that the sum of their squares is $a^2 + b^2 = 289$.We know the algebraic identity: $(a + b)^2 = a^2 + b^2 + 2ab$.Substituting the given values into the identity:$(a + b)^2 = 289 + 2(120)$.$(a + b)^2 = 289 + 240$.$(a + b)^2 = 529$.Taking the square root on both sides,we get $a + b = \sqrt{529} = 23$.Thus,the sum of the two numbers is $23$.

The product of two numbers is $120$. The sum of their squares is $289$. The sum of the two numbers is

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