The product of the zeros of the polynomial kx | vedclass

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(A) For a cubic polynomial of the form $ax^{3}+bx^{2}+cx+d$,the product of its zeros is given by the formula $-\frac{d}{a}$.Comparing the given polyno

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$\frac{3}{2}$

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(A) For a cubic polynomial of the form $ax^{3}+bx^{2}+cx+d$,the product of its zeros is given by the formula $-\frac{d}{a}$.Comparing the given polynomial $kx^{3}-6x^{2}+11x-6$ with the standard form,we have $a=k$,$b=-6$,$c=11$,and $d=-6$.The product of the zeros is given as $4$.Therefore,$-\frac{-6}{k} = 4$.$\frac{6}{k} = 4$.$4k = 6$.$k = \frac{6}{4} = \frac{3}{2}$.

The product of the zeros of the polynomial $kx^{3}-6x^{2}+11x-6$ is $4$. Find the value of $k$.

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