The product formed on the reaction of ethyl alcohol with bleaching powder is:

An organic compound $A$ $(C_4H_9Cl)$ on reaction with $Na$ in diethyl ether gives a hydrocarbon,which on monochlorination gives only one chloro derivative. $A$ is:

Arrange the compounds of each set in order of reactivity towards $S_{N}2$ displacement:
$(i)$ $2-Bromo-2-methylbutane$,$1-Bromopentane$,$2-Bromopentane$
$(ii)$ $1-Bromo-3-methylbutane$,$2-Bromo-2-methylbutane$,$2-Bromo-3-methylbutane$
$(iii)$ $1-Bromobutane$,$1-Bromo-2,2-dimethylpropane$,$1-Bromo-2-methylbutane$,$1-Bromo-3-methylbutane$.

Which of the following alkyl halides gives only one product (excluding stereoisomers) when undergoing an $E_2$ reaction? $(E_2 = \text{elimination bimolecular})$

$3$-Phenylpropene on reaction with $HBr$ gives (as a major product)

Which is the correct reactivity order for $E_2$ reaction with alcoholic $KOH$?