$3$-Phenylpropene on reaction with $HBr$ gives (as a major product)

  • A
    $C_6H_5CH_2CH(Br)CH_3$
  • B
    $C_6H_5CH(Br)CH_2CH_3$
  • C
    $C_6H_5CH_2CH_2CH_2Br$
  • D
    $C_6H_5CH(Br)CH = CH_2$

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