The probability that a person is not a sports | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $p$ be the probability that a person is a sportsperson and $q$ be the probability that a person is not a sportsperson. Given $q = \frac{1}{6}$

Vedclass · Accepted Answer

$6 	imes \left(\frac{5}{6}ight)^5 	imes \frac{1}{6}$

Vedclass · Answer

(B) Let $p$ be the probability that a person is a sportsperson and $q$ be the probability that a person is not a sportsperson. Given $q = \frac{1}{6}$,so $p = 1 - q = 1 - \frac{1}{6} = \frac{5}{6}$. We have $n = 6$ members in the family. We want to find the probability that $x = 5$ members are sportspersons. Using the Binomial distribution formula $P(X = x) = ^nC_x 	imes p^x 	imes q^{n-x}$: $P(X = 5) = ^6C_5 	imes \left(\frac{5}{6}ight)^5 	imes \left(\frac{1}{6}ight)^{6-5}$ $P(X = 5) = 6 	imes \left(\frac{5}{6}ight)^5 	imes \frac{1}{6}$ Thus,the probability is $6 	imes \left(\frac{5}{6}ight)^5 	imes \frac{1}{6}$.

The probability that a person is not a sportsperson is $\frac{1}{6}$. Then the probability that out of the $6$ members of the family,$5$ are sportspersons is

Similar Questions

$A$ die is thrown $6$ times. If 'getting an odd number' is a success,what is the probability of at least $5$ successes?

If the sum and the product of the mean and variance of a binomial distribution are $24$ and $128$ respectively,then the probability of one or two successes is:

On a multiple choice examination with three possible answers for each of the five questions,what is the probability that a candidate would get four or more correct answers just by guessing?

If the mean and variance of a binomial variate $X$ are $2$ and $1$ respectively,then the probability that $X$ takes a value greater than $1$ is

$A$ man tosses a coin $10$ times,scoring $1$ point for each head and $2$ points for each tail. Let $P(K)$ be the probability of scoring at least $K$ points. The largest value of $K$ such that $P(K) > \frac{1}{2}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module