The probability that a non-leap year selected at random will have $53$ Sundays or $53$ Saturdays is

$A$ and $B$ are two events such that $P(A)=0.58$,$P(B)=0.32$ and $P(A \cap B)=0.28$. Then the probability that neither $A$ nor $B$ occurs is

Two dice are thrown simultaneously. The probability of getting the sum $2$,$8$,or $12$ is

Describe the sample space for the indicated experiment: $A$ coin is tossed three times.

Let $E_{1}, E_{2}, E_{3}$ be three mutually exclusive events such that $P(E_{1}) = \frac{2+3p}{6}$,$P(E_{2}) = \frac{2-p}{8}$,and $P(E_{3}) = \frac{1-p}{2}$. If the maximum and minimum values of $p$ are $p_{1}$ and $p_{2}$,then $(p_{1} + p_{2})$ is equal to.

The probability that an ordinary or a non-leap year has $53$ Sundays is