The probability that a leap year selected randomly will have $53$ Sundays is
The probability that a leap year selected randomly will have $53$ Sundays is
- A
$\frac{1}{7}$
- B
$\frac{2}{7}$
- C
$\frac{4}{{53}}$
- D
$\frac{4}{{49}}$
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- [IIT 1994]
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