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(B) leap year contains $366$ days,which is equal to $52$ weeks and $2$ extra days.There are definitely $52$ Sundays in the $52$ full weeks.For the rem

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$\frac{2}{7}$

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(B) leap year contains $366$ days,which is equal to $52$ weeks and $2$ extra days.There are definitely $52$ Sundays in the $52$ full weeks.For the remaining $2$ days,the possible combinations are:$(i)$ Sunday and Monday,$(ii)$ Monday and Tuesday,$(iii)$ Tuesday and Wednesday,$(iv)$ Wednesday and Thursday,$(v)$ Thursday and Friday,$(vi)$ Friday and Saturday,$(vii)$ Saturday and Sunday.There are $7$ total possible outcomes for the remaining $2$ days.For the year to have $53$ Sundays,one of the two remaining days must be a Sunday.This occurs in $2$ cases: $(i)$ Sunday and Monday,and $(vii)$ Saturday and Sunday.Therefore,the required probability is $\frac{2}{7}$.

The probability that a leap year selected randomly will have $53$ Sundays is

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