In a throw of three dice, the probability that at least one die shows up $1$, is
$\frac{5}{6}$
$\frac{{91}}{{216}}$
$\frac{1}{{36}}$
$\frac{{125}}{{216}}$
The probability of happening an event $A$ in one trial is $0.4$. The probability that the event $A$ happens at least once in three independent trials is
Two dice are thrown. The events $A, B$ and $C$ are as follows:
$A:$ getting an even number on the first die.
$B:$ getting an odd number on the first die.
$C:$ getting the sum of the numbers on the dice $\leq 5$
Describe the events not $B$
The probability that a marksman will hit a target is given as $1/5$. Then his probability of at least one hit in $10$ shots, is
A pair of a dice thrown, if $5$ appears on at least one of the dice, then the probability that the sum is $10$ or greater is
Two dice are tossed. The probability that the total score is a prime number is