The probability of choosing at random a numbe | vedclass

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(d) We have, the number of divisible by $6$ in the series form $1$ to $90$ is $15$.

$	herefore $ Number divisible by $8$ in the series from $1$ to

Vedclass · Accepted Answer

$\frac{{23}}{{90}}$

Vedclass · Answer

(d) We have, the number of divisible by $6$ in the series form $1$ to $90$ is $15$.

$	herefore $ Number divisible by $8$ in the series from $1$ to $90$ is equal to $11$ and the number divisible by both $6$ and $8$ in series from $1$ to $90 = 3.$

$	herefore $ Probability of choosing the number divisible by $6$ or $8$ is

$P = \frac{{15 + 11 - 3}}{{90}}$ or $P = \frac{{23}}{{90}}$.

The probability of choosing at random a number that is divisible by $6$ or $8$ from among $1$ to $90$ is equal to

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