The probability distribution of a random variable $X$ is given below.
$X = x$ $0$ $1$ $2$ $3$
$P(X = x)$ $\frac{1}{10}$ $\frac{2}{10}$ $\frac{3}{10}$ $\frac{4}{10}$

Then the variance of $X$ is

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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If $X$ is a random variable with cumulative distribution function $F(x)$ and its probability distribution is given by the following table:
$X = x$$-1.5$$-0.5$$0.5$$1.5$$2.5$
$P(X = x)$$0.05$$0.2$$0.15$$0.25$$0.35$

Then,find the value of $F(1.5) - F(-0.5)$.

The random variable $X$ has the following probability distribution:
| $X$ | $8$ | $12$ | $16$ | $20$ | $24$ |
|---|---|---|---|---|---|
| $P(X)$ | $K$ | $\frac{1}{6}$ | $\frac{3}{8}$ | $2K$ | $\frac{1}{12}$ |
Then the value of $K$ is:

If $X$ is a Poisson variate such that $\frac{5}{3} k = P(X=2) = P(X=3)$,then $P(X=5) =$

If $X$ is a random variable with the distribution given below:
$X = x_i$$0$$1$$2$$3$
$P(X = x_i)$$k$$3k$$3k$$k$

Then the value of $k$ and its variance are respectively given by:

Four defective oranges are accidentally mixed with sixteen good ones. Three oranges are drawn from the mixed lot. The probability distribution of defective oranges is

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