The probabilities of three mutually exclusive events are $\frac{2}{3}$,$\frac{1}{4}$,and $\frac{1}{6}$. The statement is:

$A$ party of $23$ persons take their seats at a round table. The odds against two specific persons sitting together are

If a card is drawn at random from a well-shuffled pack of $52$ playing cards,then the probability that it is either an ace or a spade card is

If $A$ and $B$ are events such that $P(A \cup B) = \frac{5}{6}$,$P(\bar{A}) = \frac{1}{4}$,and $P(B) = \frac{1}{3}$,then $A$ and $B$ are

Two candidates $A$ and $B$ have attended an interview conducted by a recruitment board for two jobs. If the probability that candidate $A$ will get the job is $0.8$ and the probability that candidate $B$ will get the job is $0.7$,then the probability that at least one of them will get the job is

$A$ coin is tossed twice. If events $A$ and $B$ are defined as: $A = \text{head on first toss}$,$B = \text{head on second toss}$. Then the probability of $A \cup B = $