The preferred sites of protonation in the fol | vedclass

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(A) In compound $(i)$,$N$-methylacetamide,the oxygen atom $(1)$ is more basic than the nitrogen atom $(2)$ because the lone pair on the nitrogen is in

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$1$ and $3$

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(A) In compound $(i)$,$N$-methylacetamide,the oxygen atom $(1)$ is more basic than the nitrogen atom $(2)$ because the lone pair on the nitrogen is involved in resonance with the carbonyl group,reducing its availability for protonation.In compound $(ii)$,$2$-aminopyridine,the ring nitrogen $(3)$ is more basic than the amino group nitrogen $(4)$. The lone pair on the amino group nitrogen is delocalized into the pyridine ring,whereas the lone pair on the ring nitrogen is in an $sp^2$ orbital and is available for protonation.Therefore,the preferred sites of protonation are $1$ and $3$.

The preferred sites of protonation in the following compounds are:
$(i)$ $CH_3CONHCH_3$
(ii) $2$-aminopyridine

Similar Questions

The major product $(x)$ in the following reaction is:

What is the correct order of basicity for the following compounds?
$1$. $C_6H_5NH_2$ (Aniline)
$2$. $CH_3CH_2NH_2$ (Ethylamine)
$3$. $(CH_3)_2NH$ (Dimethylamine)
$4$. $CH_3CONH_2$ (Acetamide)

When aniline is nitrated with nitrating mixture in ice-cold condition,the major product obtained is

The increasing order of nucleophilicity of the following nucleophiles is: $a. CH_3CO_2^-$,$b. H_2O$,$c. CH_3SO_3^-$,$d. OH^-$

Identify the $X$ in the reaction.
$R-NH_2 + HNO_2 \underset{273-278 \ K}{}$ ${\xrightarrow{NaNO_2 + HCl}} X$ $\xrightarrow{H_2O} R-OH + N_2 + HCl$

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The preferred sites of protonation in the following compounds are:$(i)$ $CH_3CONHCH_3$(ii) $2$-aminopyridine