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(B) The power $P$ delivered to the device is given by $P = V I$,where $V$ is the voltage and $I$ is the current flowing through the wires.From this,th

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$\frac{P^2 R_C}{V^2}$

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(B) The power $P$ delivered to the device is given by $P = V I$,where $V$ is the voltage and $I$ is the current flowing through the wires.From this,the current $I$ can be expressed as $I = \frac{P}{V}$.The power wasted in the connecting wires due to their finite resistance $R_C$ is given by the formula $P_C = I^2 R_C$.Substituting the expression for $I$ into the power loss formula,we get $P_C = \left( \frac{P}{V} \right)^2 R_C$.Therefore,the power wasted is $P_C = \frac{P^2 R_C}{V^2}$.

The power wasted in the connecting wires of voltage $V$ and finite resistance $R_C$ from the power station to the device of power $P$ is . . . . . . .

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