The power utilized when a force of (2 hat{i}+ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Force $\vec{F} = (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) 	ext{ N}$, Displacement $\vec{s} = (3 \hat{i} + 4 \hat{j} + 5 \hat{k}) 	ext{ m}$, Ti

Vedclass · Accepted Answer

$9.5$

Vedclass · Answer

(A) Given: Force $\vec{F} = (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) 	ext{ N}$, Displacement $\vec{s} = (3 \hat{i} + 4 \hat{j} + 5 \hat{k}) 	ext{ m}$, Time $t = 4 	ext{ s}$.Average velocity $\vec{v} = \frac{\vec{s}}{t} = \frac{1}{4}(3 \hat{i} + 4 \hat{j} + 5 \hat{k}) 	ext{ m/s}$.Power $P = \vec{F} \cdot \vec{v}$.$P = (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) \cdot \frac{1}{4}(3 \hat{i} + 4 \hat{j} + 5 \hat{k})$.$P = \frac{1}{4} [(2 	imes 3) + (3 	imes 4) + (4 	imes 5)]$.$P = \frac{1}{4} [6 + 12 + 20] = \frac{38}{4} = 9.5 	ext{ W}$.

The power utilized when a force of $(2 \hat{i}+3 \hat{j}+4 \hat{k}) \text{ N}$ acts on a body for $4 \text{ s}$, producing a displacement of $(3 \hat{i}+4 \hat{j}+5 \hat{k}) \text{ m}$, is (in $\text{ W}$)

Similar Questions

Power of a water pump is $2 \, kW$. If $g = 10 \, m/s^2$,the amount of water it can raise in one minute to a height of $10 \, m$ is .............. $liter$.

$A$ pump is required to lift $1000 \, kg$ of water per minute from a well of depth $10 \, m$ and eject it with a speed of $10 \, m/s$. The horsepower of the engine needed is: (Assume $g = 10 \, m/s^2$)

$A$ body is moving unidirectionally under the influence of a constant power source. Its displacement in time $t$ is proportional to :

An electric motor exerts a force of $50 \,N$ on a cable and pulls it through $60 \,m$ in $1 \,min$. The power supplied by the motor is (in $\,W$)

If $\overrightarrow{F} = (60 \hat{i} + 15 \hat{j} - 3 \hat{k}) \; N$ and $\overrightarrow{V} = (2 \hat{i} - 4 \hat{j} + 5 \hat{k}) \; m/s$,then the instantaneous power is: (in $; W$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module