A pump is required to lift 1000 , kg of water | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total power required is the sum of the power needed to lift the water against gravity and the power needed to provide kinetic energy to the wa

Vedclass · Accepted Answer

$3.33$

Vedclass · Answer

(A) The total power required is the sum of the power needed to lift the water against gravity and the power needed to provide kinetic energy to the water.Power $P = \frac{W}{t} = \frac{mgh + \frac{1}{2}mv^2}{t}$Given: $m = 1000 \, kg$,$t = 60 \, s$,$h = 10 \, m$,$v = 10 \, m/s$,$g = 10 \, m/s^2$.$P = \frac{1000 	imes 10 	imes 10 + \frac{1}{2} 	imes 1000 	imes (10)^2}{60}$$P = \frac{100000 + 50000}{60} = \frac{150000}{60} = 2500 \, W$.Since $1 \, HP = 746 \, W$,the power in horsepower is:$P_{HP} = \frac{2500}{746} \approx 3.35 \, HP$.Rounding to the nearest provided option,the answer is $3.33 \, HP$.

$A$ pump is required to lift $1000 \, kg$ of water per minute from a well of depth $10 \, m$ and eject it with a speed of $10 \, m/s$. The horsepower of the engine needed is: (Assume $g = 10 \, m/s^2$)

Similar Questions

$A$ pump is used to deliver water at a certain rate from a given pipe. To obtain $n$ times the water in the same time from the same pipe,by what factor should the power of the motor be increased?

The force required to row a boat at constant velocity is proportional to the square of its speed. If a speed of $v \, km/h$ requires $4 \, kW$ of power,how much power does a speed of $2v \, km/h$ require?

Why is electrical power required at all when the elevator is descending? Why should there be a limit on the number of passengers in this case?

The power of a water pump is $2 \; kW$. If we take $g = 10 \; m/s^2$, how many liters of water can be raised to a height of $10 \; m$ in one minute?

$A$ body of mass '$M$' is moving with a uniform speed of '$v$' on a frictionless horizontal surface under the influence of two forces $F_1$ and $F_2$ as shown in the figure. The net power of the system is

Vedclass Test Series

Exam Paper Generator

Online Exam Module