The potential of the electric field produced by a point charge at any point $(x, y, z)$ is given by $V = 3x^2 + 5$,where $x, y$ are in metres and $V$ is in volts. The intensity of the electric field at $(-2, 1, 0)$ is

Due to some charges on the $x$-axis,the potential at a point on the $x$-axis is given by $V(x) = 20/(x^2 - 4) \ V$. The electric field at $x = 4 \ \mu m$ is given by:

If the electric potential is given by $V = (5x^2 + 10x - 9) \ V$,what is the electric field at $x = 1 \ m$ in $V/m$?

The potential difference between two points $A(2, 1, 0) \ m$ and $B(0, 2, 4) \ m$ in an electric field $\vec{E} = (x \hat{i} - 2y \hat{j} + z \hat{k}) \ Vm^{-1}$ is: (in $V$)

The electric field in a region surrounding the origin is uniform and along the $x$-axis. $A$ small circle is drawn with the centre at the origin,cutting the axes at points $A, B, C, D$ having coordinates $(a, 0), (0, a), (-a, 0), (0, -a)$ respectively,as shown in the figure. Then,the potential is minimum at the point:

An electric field $\vec{E} = (25 \hat{i} + 30 \hat{j}) \, NC^{-1}$ exists in a region of space. If the potential at the origin is taken to be zero,then the potential at $x = 2 \, m, y = 2 \, m$ is ...... $volt$.