The potential energy of a body of mass m is: | vedclass

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Question

$F_{x}=-\frac{d v}{d x}=-a$ and $F_{y}=-\frac{d v}{d x}=-b$

Net force, $F=\sqrt{F_{x}^{2}+F_{y}^{2}}=\sqrt{a^{2}+b^{2}}$

$	ext { Acceleration }

Vedclass · Accepted Answer

$\frac{{{{({a^2} + {b^2})}^{1/2}}}}{m}$

Vedclass · Answer

$F_{x}=-\frac{d v}{d x}=-a$ and $F_{y}=-\frac{d v}{d x}=-b$

Net force, $F=\sqrt{F_{x}^{2}+F_{y}^{2}}=\sqrt{a^{2}+b^{2}}$

$	ext { Acceleration }=\frac{\mathrm{F}}{\mathrm{m}}=\frac{\sqrt{\mathrm{a}^{2}+\mathrm{b}^{2}}}{\mathrm{m}}$

The potential energy of a body of mass $m$ is:
$U = ax + by$
Where $x$ and $y$ are position co-ordinates of the particle. The acceleration of the particle is

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