A body of mass M_1 collides elastically with | vedclass

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(C) In an elastic collision between two bodies,the fraction of kinetic energy transferred from the first body (mass $M_1$) to the second body (mass $M

Vedclass · Accepted Answer

$M_1 = M_2$

Vedclass · Answer

(C) In an elastic collision between two bodies,the fraction of kinetic energy transferred from the first body (mass $M_1$) to the second body (mass $M_2$) initially at rest is given by the formula: $f = \frac{4 M_1 M_2}{(M_1 + M_2)^2}$ To find the condition for maximum energy transfer,we maximize $f$ with respect to the mass ratio. Alternatively,for a one-dimensional elastic collision,if $M_1 = M_2$,the bodies exchange their velocities after the collision. Since the second body was at rest,it acquires the full initial velocity of the first body,meaning $100\%$ of the kinetic energy is transferred. Thus,the maximum transfer of energy occurs when $M_1 = M_2$.

$A$ body of mass $M_1$ collides elastically with another mass $M_2$ at rest. There is maximum transfer of energy when

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