The potential difference between the terminals of an electric heater is $60\, V$ when it draws a current of $4\, A$ from the source. What current will the heater draw, if the potential difference is increased to $120\, V$ ?
We are given, potential difference $V =60 V$ current $I=4$ $A.$
According to Ohm's law, $V = IR$ i.e., current is directly proportional to the applied potential difference.
Therefore, when the potential difference is increased to $120\, V$ i.e., made double the current will also become double. Therefore, current through the heater becomes $8 \,A.$
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