The potential difference applied to an X-ray | vedclass

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(D) The minimum wavelength (cutoff wavelength) of $X-$rays produced in an $X-$ray tube is given by the relation: $\lambda_{min} = \frac{hc}{eV}$,where

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$(A)$ and $(C)$ both

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(D) The minimum wavelength (cutoff wavelength) of $X-$rays produced in an $X-$ray tube is given by the relation: $\lambda_{min} = \frac{hc}{eV}$,where $h$ is Planck's constant,$c$ is the speed of light,$e$ is the charge of an electron,and $V$ is the accelerating potential difference.From this relation,it is clear that $\lambda_{min} \propto \frac{1}{V}$.Therefore,if the potential difference $V$ is increased,the minimum wavelength $\lambda_{min}$ decreases.Additionally,increasing the potential difference increases the energy of the incident electrons,which generally leads to an increase in the intensity of the emitted $X-$rays.Thus,both the intensity increases and the minimum wavelength decreases.

The potential difference applied to an $X-$ray tube is increased. As a result,in the emitted radiation:

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