The position of the point (8, -9) with respec | vedclass

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Question

(A) Let the two lines be $L_1: 2x + 3y - 4 = 0$ and $L_2: 6x + 9y + 8 = 0$.Substitute the point $(8, -9)$ into the equation of $L_1$:$L_1(8, -9) = 2(8

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Point lies on the same side of the lines

Vedclass · Answer

(A) Let the two lines be $L_1: 2x + 3y - 4 = 0$ and $L_2: 6x + 9y + 8 = 0$.Substitute the point $(8, -9)$ into the equation of $L_1$:$L_1(8, -9) = 2(8) + 3(-9) - 4 = 16 - 27 - 4 = -15$.Substitute the point $(8, -9)$ into the equation of $L_2$:$L_2(8, -9) = 6(8) + 9(-9) + 8 = 48 - 81 + 8 = -25$.Since both $L_1(8, -9)$ and $L_2(8, -9)$ have the same sign (both are negative),the point $(8, -9)$ lies on the same side of both lines.

The position of the point $(8, -9)$ with respect to the lines $2x + 3y - 4 = 0$ and $6x + 9y + 8 = 0$ is

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