Two boys are standing at the ends $A$ and $B$ of a ground where $AB = a$. The boy at $B$ starts running in a direction perpendicular to $AB$ with velocity ${v_1}.$ The boy at $A$ starts running simultaneously with velocity $v$ and catches the other boy in a time $t$, where $t$ is

  • [AIPMT 2005]
  • A

    $a/\sqrt {{v^2} + v_1^2} $

  • B

    $\sqrt {{a^2}/({v^2} - v_1^2)} $

  • C

    $a/(v - {v_1})$

  • D

    $a/(v + {v_1})$

Similar Questions

Two stones are thrown up vertically and simultaneously but with different speeds. Which graph correctly represents the time variation of their relative positions $\Delta x$.Assume that stones do not bounce after hitting ground.

A particle moves with constant speed $v$ along a regular hexagon $ABCDEF$ in the same order. Then the magnitude of the average velocity for its motion from $A$ to

The position of a particle moving in the $xy-$plane at any time $t$ is given by $x = (3{t^2} - 6t)$ metres, $y = ({t^2} - 2t)$ metres. Select the correct statement about the moving particle from the following

The coordinates of a moving particle at any time are given by $x = a{t^2}$ and $y = b{t^2}$. The speed of the particle at any moment is

A body starts from rest from the origin with an acceleration of $6\,m/{s^2}$ along the $x-$axis and $8\,m/{s^2}$ along the $y-$axis. Its distance from the origin after $4 \,seconds$ will be........$m$