The points in the Argand plane given by Z_1 = | vedclass

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(D) Let the points be $A(-3, 5)$,$B(-1, 6)$,$C(-2, 8)$,and $D(-4, 7)$.Calculate the lengths of the sides:$AB = \sqrt{(-1 - (-3))^2 + (6 - 5)^2} = \sqr

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square

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(D) Let the points be $A(-3, 5)$,$B(-1, 6)$,$C(-2, 8)$,and $D(-4, 7)$.Calculate the lengths of the sides:$AB = \sqrt{(-1 - (-3))^2 + (6 - 5)^2} = \sqrt{2^2 + 1^2} = \sqrt{5}$$BC = \sqrt{(-2 - (-1))^2 + (8 - 6)^2} = \sqrt{(-1)^2 + 2^2} = \sqrt{5}$$CD = \sqrt{(-4 - (-2))^2 + (7 - 8)^2} = \sqrt{(-2)^2 + (-1)^2} = \sqrt{5}$$DA = \sqrt{(-3 - (-4))^2 + (5 - 7)^2} = \sqrt{1^2 + (-2)^2} = \sqrt{5}$Since all sides are equal,it is a rhombus or a square.Calculate the lengths of the diagonals:$AC = \sqrt{(-2 - (-3))^2 + (8 - 5)^2} = \sqrt{1^2 + 3^2} = \sqrt{10}$$BD = \sqrt{(-4 - (-1))^2 + (7 - 6)^2} = \sqrt{(-3)^2 + 1^2} = \sqrt{10}$Since the diagonals are equal $(AC = BD = \sqrt{10})$ and all sides are equal,the figure is a square.

The points in the Argand plane given by $Z_1 = -3 + 5i$,$Z_2 = -1 + 6i$,$Z_3 = -2 + 8i$,and $Z_4 = -4 + 7i$ form a:

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